SQL15 查找employees表

本文最后更新于：2022年4月9日 中午


题目描述

查找employees表所有emp_no为奇数，且last_name不为Mary(注意大小写)的员工信息，并按照hire_date逆序排列(题目不能使用mod函数)

1
2
3
4
5
6
7
8
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));

如插入：

1
2
3
4
5
6
7
8
9
10
11
INSERT INTO employees VALUES(10001,'1953-09-02','Georgi','Facello','M','1986-06-26');
INSERT INTO employees VALUES(10002,'1964-06-02','Bezalel','Simmel','F','1985-11-21');
INSERT INTO employees VALUES(10003,'1959-12-03','Parto','Bamford','M','1986-08-28');
INSERT INTO employees VALUES(10004,'1954-05-01','Chirstian','Koblick','M','1986-12-01');
INSERT INTO employees VALUES(10005,'1955-01-21','Kyoichi','Maliniak','M','1989-09-12');
INSERT INTO employees VALUES(10006,'1953-04-20','Anneke','Preusig','F','1989-06-02');
INSERT INTO employees VALUES(10007,'1957-05-23','Tzvetan','Zielinski','F','1989-02-10');
INSERT INTO employees VALUES(10008,'1958-02-19','Saniya','Kalloufi','M','1994-09-15');
INSERT INTO employees VALUES(10009,'1952-04-19','Sumant','Peac','F','1985-02-18');
INSERT INTO employees VALUES(10010,'1963-06-01','Duangkaew','Piveteau','F','1989-08-24');
INSERT INTO employees VALUES(10011,'1953-11-07','Mary','Sluis','F','1990-01-22');

输入描述

无

输出描述

emp_no birth_date first_name last_name gender hire_date
10011 1953-11-07 Mary Sluis F 1990-01-22
10005 1955-01-21 Kyoichi Maliniak M 1989-09-12
10007 1957-05-23 Tzvetan Zielinski F 1989-02-10
10003 1959-12-03 Parto Bamford M 1986-08-28
10001 1953-09-02 Georgi Facello M 1986-06-26
10009 1952-04-19 Sumant Peac F 1985-02-18

题解

1
select * from employees where emp_no % 2 =1 and last_name != 'Mary' order by hire_date desc;